Solving Math Word Problems: The Jurassic Zoo Example
The Jurassic Zoo presents a fascinating scenario that can be effectively solved using basic algebra and problem-solving techniques. This example not only helps in understanding the application of algebraic equations in real-life situations but also provides a step-by-step approach to solving similar word problems. Let's explore the problem step by step and understand the logic behind it.
Setting Up the Problem
At the Jurassic Zoo, the admission fee is $8 for each adult and $4 for each child. A group of 201 people attended the zoo, and the total bill amounted to $964. Our task is to determine the number of adults and children in the group.
Formulating the Equations
Let's denote the number of adults as x. Consequently, the number of children would be 201 - x.
The total cost can be calculated using the equation:
8x 4(201 - x) 964
Breaking Down the Steps
Substitute the number of children in the equation: Substitute 201 - x for the number of children. Expand and simplify the equation: Expand the equation to simplify the left-hand side. Isolate the variable: Solve for x by isolating it on one side of the equation. Solve for the number of adults and children: Use the value of x to find the number of adults and children.Solving the Equations
8x 4(201 - x) 964
8x 804 - 4x 964
4x 804 964
4x 964 - 804
4x 160
x 40
So, there are 40 adults at the zoo.
Number of children: 201 - x 201 - 40 161
By solving the equations, we have determined that there are 40 adults and 161 children at the Jurassic Zoo.
Conclusion
Using algebraic equations, we have successfully determined the number of adults and children at the Jurassic Zoo. This example not only helps in understanding the application of algebraic equations in real-life scenarios but also provides a clear insight into problem-solving techniques. Such exercises are essential for building a strong foundation in mathematics and enhancing problem-solving skills.